solve the equation 6x^2-24=0

Question

8x^2-128=0 it is a algebra 1 question it says to solve the equation

Answer 1

x = +2, -2

Answer 2

Solve the equation 6x^2-24=0

8x²-128=0 it is a algebra 1 question it says to solve the equation

 

8x² -128 = 0

 

8x² = 128         [Add 128 to both sides of the equation]

 

x² = 16             [Divide both sides by 8]

 

√x² = √16        [Take the square root of both sides]

 

x = ±4

 

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6x² - 24 = 0

 

6x² = 24           [Add 24 to both sides]

 

x² = 4              [Divide both sides by 6]

 

Can you finish it from here?