Solve the equation 6x^2-24=0
8x^{2}-128=0 it is a algebra 1 question it says to solve the equation
8x^{2} -128 = 0
8x^{2} = 128 [Add 128 to both sides of the equation]
x^{2} = 16 [Divide both sides by 8]
√x^{2} = √16 [Take the square root of both sides]
x = ±4
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6x^{2} - 24 = 0
6x^{2} = 24 [Add 24 to both sides]
x^{2} = 4 [Divide both sides by 6]
Can you finish it from here?