Solve the equation 6x^224=0
8x^{2}128=0 it is a algebra 1 question it says to solve the equation
8x^{2} 128 = 0
8x^{2} = 128 [Add 128 to both sides of the equation]
x^{2} = 16 [Divide both sides by 8]
√x^{2} = √16 [Take the square root of both sides]
x = ±4

6x^{2}  24 = 0
6x^{2} = 24 [Add 24 to both sides]
x^{2} = 4 [Divide both sides by 6]
Can you finish it from here?
4/25/2014

Philip P.