solve the equation for 0 less than or equal to x less than 2 pie

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Assuming you mean ( 0 <= x < 2Pi)

-2 Cos(x) + √3 = 0

-2 Cos(x) = - √3

Cos(x) = (-V3)/(-2) = √3/2

Can you get from there to the solution?

the possible results are x = Pi/6 , 11Pi/6

uhmm i kind of confused i can you explain further?

i mean this 0≤ x < 2 pie

Sure.

Once you get to

Cos(x) = (-V3)/(-2) = √3/2

you have isolated the variable. So now you need to find x.

Since taking the cos of x gives √3/2 [that is (√3) / 2 not √(3/2) ]

Then the inverse function will bring √3/2 back to x

[ function N = M then inverse function M - N ]

Cos(x) = √3/2

Inverse cos √3/2 = arc-cos √3/2 = cos^{-1} √3/2

Find the inverse cos of √3/2 on your calculator.

Then pick the ones that are between 0≤ x < 2 Pi

The two answers I gave you ( Pi/6 & 11Pi/6 ) are the exact values solving using maths.

The decimal values you get on your calculator will be approximate values since the calculator needs to round off Pi.

BTW - it is pi not pie

OOPS - sorry

The [ function N = M then inverse function M - N ]

should be [ function N = M then inverse function M = N ]

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