I don't understand how to do this and I am very confused.

4x+6y=12

3x+5y=18

If you want to solve the linear system by multiplying, pick a variable to eliminate. If you choose the x, multiply the line by the x coefficient of the other line.

3(4x+6y=12)

4(3x+5y=18)

4(3x+5y=18)

Distribute the factor to each term.

12x+18y=36

12x+20y=72

Subtract each term from the line above

12x+18y=36

-(12x+20y=72)

0 - 2y =-36

Solve for y.

y=18

Plug the value for y into one of the original equations and solve for x.

3x+5(18)=18

3x+90=18

3x=-72

x=-24

(-24,18) works for both equations.

There are variations to the method I used, but the solution will stay the same.

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