59535 = 5(11907) = (5)(3)(3969)
= (5)(3)(3)(1323)
= (5)(3)(3)(3)(441)
= (5)(3)(3)(3)(3)(147)
= (5)(3)(3)(3)(3)(7)(3)(7)
= 72355
We will have a perfect square if all of the exponents are even. so, multiplying by 15 = (3)(5) gives 723652 = [7(3)3(5)]2
The sum of the digits of 15 is 6.
Mark M.
tutor
The digits of the number 15 are 1 and 5. The sum of 1 and 5 is 6.
Report
05/30/17
MD MERAZ A.
05/30/17