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How to solve quadratic functions that contain fractions?

What is the best way to solve a quadratic equation that contains fractions? An example is 1/2x - 2x = 3/2

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The quadratic equation still works:
 
(-b/2a) ± (1/2a)(b2 - 4ac)1/2
 
In your example, a = 1/2, b=-2, c = -3/2
 
[2/(2)(1/2)] ± ((-2)2 - 4(1/2)(-3/2))1/2
 
(2/1) ± (4+3)1/2 = 2 ± √7
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2 Answers

What is the best way to solve a quadratic equation that contains fractions? An example is 1/2x^2 - 2x = 3/2.
 
I multiply both sides by a number that gets rid of the denominators of all the fractions. E.g.,
 
Multiply your example by 2 on both sides:
 
x^2 – 4x = 3
 
x^2 – 4x – 3 = 0
 
Using Quadratic Formula:
 
x = (4 ± √(16–4(1)(–3)))/(2(1))
 
x = 2 ± √(4–(1)(–3))
 
x = 2 ± √(7)
Just Multiply both sides by LCM of the denominators of the fractions. It works for all equations.