0

# How to solve quadratic functions that contain fractions?

What is the best way to solve a quadratic equation that contains fractions? An example is 1/2x - 2x = 3/2

### Comments

The quadratic equation still works:

(-b/2a) ± (1/2a)(b2 - 4ac)1/2

In your example, a = 1/2, b=-2, c = -3/2

[2/(2)(1/2)] ± ((-2)2 - 4(1/2)(-3/2))1/2

(2/1) ± (4+3)1/2 = 2 ± √7

### 2 Answers by Expert Tutors

Tutors, sign in to answer this question.
Steve S. | Tutoring in Precalculus, Trig, and Differential CalculusTutoring in Precalculus, Trig, and Diffe...
5.0 5.0 (3 lesson ratings) (3)
-1
What is the best way to solve a quadratic equation that contains fractions? An example is 1/2x^2 - 2x = 3/2.

I multiply both sides by a number that gets rid of the denominators of all the fractions. E.g.,

Multiply your example by 2 on both sides:

x^2 – 4x = 3

x^2 – 4x – 3 = 0

Using Quadratic Formula:

x = (4 ± √(16–4(1)(–3)))/(2(1))

x = 2 ± √(4–(1)(–3))

x = 2 ± √(7)
Parviz F. | Mathematics professor at Community CollegesMathematics professor at Community Colle...
4.8 4.8 (4 lesson ratings) (4)
-1
Just Multiply both sides by LCM of the denominators of the fractions. It works for all equations.