Arthur D. answered 05/17/17
Tutor
5.0
(254)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
A=(0,0), B=(b,0), C=(b+c,d), D=(c,d)
use the distance formula
DC=√(c-[b+c])2+(d-d)2
DC=√b2
DC=b
AB=√(0-b)2+(0-0)2
AB=√(-b)2
AB=√b2
AB=b
therefore DC=AB
DA=√(c-0)2+(d-0)2
DA=√c2+d2
CB=√(b+c-b)2+(d-0)2
CB=√c2+d2
therefore DA=CB