x^2+7x+12/(x=6)(x+3)

Question

Trying to simplify

Answer 1

(x^2+7x+12)/((x+6)(x+3))

 

= (x+3)(x+4)/((x+6)(x+3))

 

Now we want to "cancel" the x+3 factor in both the numerator and denominator. However, note that:

 

(x+3)/(x+3) = {1 if x ≠ –3, UNDEFINED if x = –3}

 

So we need to constrain our simplified answer:

 

(x+4)/(x+6), x ≠ –3