What is it used for?

Provide a useful example of a quadratic equation for someone to solve. Show your steps or at least some of your steps in how you derived to your final answer. Please do not show just the final answer

What is the quadratic formula?

What is it used for?

Provide a useful example of a quadratic equation for someone to solve. Show your steps or at least some of your steps in how you derived to your final answer. Please do not show just the final answer

What is it used for?

Provide a useful example of a quadratic equation for someone to solve. Show your steps or at least some of your steps in how you derived to your final answer. Please do not show just the final answer

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Stephanie T. | Stephanie, Education ExtraordinaireStephanie, Education Extraordinaire

The quadratic formula is a formula by which you can compute the X value of a function by using the components in its equation when Y=0, or the function crosses the x-axis. (This applies only when
*a* does not = 0)

The quadratic equation is as follows:

x= -b ± √(b^{2} - 4ac)

2a

where the function is

ax^{2}+bx+c = y --> ax2+bx+c = 0

Example:

Find the solution X to the function y= x^{2 }- 3x - 10 using the quadratic equation.

Find the solution X to the function y= x

So if y=0,

Then:

A= 1

B= -3

C= -10

Therefore:

x= -(-3) ± √((-3)^{2} - 4(1)(-10)) =
3 ± √(49) = 3 ± 7 = 5 and -2

2(1) 2 2

The solutions are -2 and 5.

This means that when y=0, or when the function crosses the x-axis, the x-values are -2 and 5.

The points at which the function crosses the x-axis are: (-2,0) and (5, 0)

:)

:)

Parviz F. | Mathematics professor at Community CollegesMathematics professor at Community Colle...

Quadratic formula is the formula for solution of Zero's of the quadratic( i.e.)

Given a quadratic Y = ax^2 + bx + c

Roots are values of X's that make y equal 0.

Values of X that make Y equal 0 is given by Quadratic formula of:

X = - b/2a ± √(b^2 - 4ac)/2a

It is driven from factoring of aX^2 + bX + c , by completing the square. as follows

a X^2 + bx + c =0

a ( X^2 + b/a x +c/a ) =0

we add ,and Subtract to inside the parenthesis (b^2 /4a^2 )

( X^2 + **2** b/**2**a **+ 4b^2 /4a^2**** **+ c/a **-4b^2/ 4a^2) =
**0

( X + b/2a) ^2 = 4b^2/ 4a^2 - c/a

( X+ b/2a ) ^2 = ( b^2 - 4ac ) / 4a^2

Taking square roots of both sides:

X + b/2a =± √(b^2 - 4ac) / 2a

X = - b/2a ±√(b^2 - 4ac ) / 2a

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