Find four consecutive even integers?

Question

Find four consecutive even integers such that -6 times the sum of the second and the fourth is less than 11 times the opposite of the third.? 

Answer 1

x-2, x-1, x, x+1

-6(x-1 + x+1) < 11(-x)

-6(2x) < -11x

-12x < -11x

divide by x to get

-12 < -11

which is true for any real value of x

x = any real number, (-infinity, infinity)