
Steve S. answered 03/27/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
If f(x) = √(x^2-1) and g(x) = √(x-1), then,
for x>1, f(x)/g(x) = √(x^2-1)/√(x-1)
= √((x^2-1)/(x-1)) = √((x+1)(x-1)/(x-1))
= √(x+1), x>1.