hello can you help me pleas

Question

Write an equation for a line perpendicular to  y=-5x+5 and passing through the point (15,6)

 

y=?

Answer 1

A line perpendicular to this line y = -5x + 5 will have the negative reciprocal slope of it.

 

y = mx + b is the slope-intercept form of the equation of a line

 

The given line has slope -5

 

The new line will have slope 1/5, and it passes thru (15, 6)

 

We can use the point-slope form of the equation of a line 

 

y - y₀ = m(x - x₀)

 

where m = slope and (x₀, y₀) is a point on the line

 

y - 6 = 1/5(x - 15)

 

y - 6 = 1/5 x - 3

 

y = 1/5 x + 3