
Vincent B. answered 04/20/17
Tutor
5
(46)
Graduate Level Math Tutor Specializing in Finite
So this is a system of equations. Our two equations are lines, right? Like we could plot -5x+y=-3 on a graph, then we could plot 3x-8y=24 and see whether they:
1)cross each other(and then figure out the x and y values by looking at the graph
2)are parallel(thus never touch)
or
3)are actually the same line
Luckily we don't need to graph to do this, but it's good to know we COULD do that. Instead we'll use either 'substitution' or 'elimination.'
Substitution is where you take one of your equations, solve for one of the variables(make it look like 'x=stuff' or 'y=stuff'), then plug that "stuff" in where the variable is in the 2nd equation. If we did that with this system, it'd look like this:
-5x+y=-3
3x-8y=24
hmm, probably should solve for y in the top equation because otherwise I'm dividing everything by -5, 3, or -8.
-5x+y=-3
+5x +5x
y = 5x-3
Now I plug 5x - 3 in wherever I see a 'y' in the 2nd equation
3x - 8(5x - 3) = 24
this is useful because now I just have x terms in this equation. After distributing the -8 through 5x - 3 I get this:
3x - 40x + 24 = 24
-33x = 0
x = 0
now I can solve for y by plugging in my value for x into either equation. I'll pick the first one.
-5(0) + y = -3
y = -3
You could also do elimination for this problem, but substitution turned out to be the easiest.
-5x+y=-3
3x-8y=24
hmm, probably should solve for y in the top equation because otherwise I'm dividing everything by -5, 3, or -8.
-5x+y=-3
+5x +5x
y = 5x-3
Now I plug 5x - 3 in wherever I see a 'y' in the 2nd equation
3x - 8(5x - 3) = 24
this is useful because now I just have x terms in this equation. After distributing the -8 through 5x - 3 I get this:
3x - 40x + 24 = 24
-33x = 0
x = 0
now I can solve for y by plugging in my value for x into either equation. I'll pick the first one.
-5(0) + y = -3
y = -3
You could also do elimination for this problem, but substitution turned out to be the easiest.


Vincent B.
Ah, I did make a mistake. Dropped an 'x' as I was moving through. Still getting used to answering questions for students in this format! Edited now.
Report
04/20/17
Kenneth S.
04/20/17