
Arturo O. answered 04/20/17
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If the variable is x, with a, b, and c being constants, then you will have a quadratic equation in x, which will have at most 2 solutions.

Arturo O.
Expand (x - a)(x - b) = c2 and get
x2 - bx - ax + ab = c2
Group like terms and get
x2 - (b + a)x + (ab - c2) = 0
Note this is an equation of the form
Ax2 + Bx + C = 0,
which is a quadratic equation, with
where A = 1, B = -(b + a), and C = ab - c2
Its solution is
x = [-B ± √(B2 - 4AC)] / (2A)
This gives at most 2 different solutions if the argument of the square root is not zero.
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04/20/17
Irene S.
04/20/17