equation of line slopes

Question

what is the equation of the line with a slope of -1/2 that passes through the point (6,-6)

Answer 1

Hi Cameron, use the point-slope form of the line to solve this problem.

 

Point-slope form:

 

y - y₁ = m * (x - x₁)

 

Substitution:

 

y₁ = -6

 

x₁ = 6

 

m = -1/2

 

y - (-6) = -1/2 * (x - 6)

 

y + 6 = -1/2 * (x - 6)

 

Multiply the entire equation by 2 to clear the fraction:

 

2y + 6 = -1 * (x - 6)

 

2y + 12 = -x + 6

 

Put into standard form, Ax + By = C:

 

x + 2y = -6

 

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