Hi Caitlyn, this is a long problem but keep trying and it'll work out.
let the function be:
y = beax+c
since, horizontal asymptote at y= 6, c = 6
plug in both points into original equation:
at (0,0)
0 = be0 + 6
b = -6
at (1,3)
3 = -6ea*1 +6
a = -ln2
final equation should then be:
y = -6 e-xln2 + 6
recall a*lnx ≡ lnxa
y = -6e^(ln2-x) +6
recall elna = a
y = -6(2-x) +6
Always make the habit of checking your solution with the points given.
Arturo O.
04/13/17