Didnt fit so it is in description please explain

Question

Thomas drove 504 miles to Stone Mountain in 9 hours. When he drove back home from Stone Mountain, his rate of speed was 2.24 times greater. What is the difference, in miles per hour, between the two rates of speed?

 

Answer 1

Hi Akshara, apply the D(istance) = R(ate) * T(ime) equation to solve this problem.

 

Rate to Stone Mountain:

 

D = R * T

 

504 = R * 9

 

R = 56

 

Thomas's speed or rate of travel to Stone Mountain was 56 mph.

 

Return from Stone Mountain:

 

R = 2.24 * 56

 

R = 125.44

 

Thomas's speed or rate of travel from Stone Mountain was 125.44 mph.

 

The difference in speed is: 125.44 - 56, or 69.44 mph.

 

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