
Michael C. answered 04/05/17
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let the mass of A required be a
let the mass of B required be b
final mixture is 170 * 55% = 93.5 grams of salt
a + b = 170 (1) (total mass of solution)
0.45a + 0.70b = 93.5 (2) (proportion of each solution required in final salt solution)
multiply (1) by -0.45
-0.45a - 0.45b = -76.5 (3)
add (2) to (3) ; 0.25b = 17
therefore b = 17/0.25 = 68
from (1) a = 170 - 68 = 102
Therefore 68 grams of B and 102 grams of A are required for the final solution mixture