Michael C. answered 04/03/17
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Let the number of quarters be q, and the number of dimes be d
q + d = 13 (1) (number of coins)
0.25q + 0.1d = 2.50 (2) (value of coins)
2.5q + d = 25 (3); (2)*10
(3) - (1) ; 1.5q = 12 ; q = 12/1.5 = 8 (eliminating d)
from (1) d = 13 - q = 13 - 8 = 5 (substituting the value of q to get d)
There are 8 quarters and 5 dimes