Find the distance and time

Question

In 1920, the record for a certain race was 45.5 sec. In 1970, it was 45.0 sec. Let R(t)equals=the record in the race and t=the number of years since 1920. a) Find a linear function that fits the data. b) Use the function in (a) to predict the record in 2003 and in 2006. c) Find the year when the record will be 44.55 sec.

Answer 1

t= 45.5-.5y/50 where y = years since 1920

t= 45.5- y/100

for 2003, y= 83,

for 2006, y=86

t(83)= 45.5-83/100= 44.67

t(88)= 44.64

44.55= 45.5-.95, y=95 means 1920+95= the year 2015