x^2+4x=2x^2-x+6

Question

Hi um I have been having trouble with this math problem. The directions said just to solve the equation.

Answer 1

Hi Olivia;

x^2+4x=2x^2-x+6

Let's bring everything to one side...

x²+4x-2x²+x-6=0

Combine like terms...

-x²+5x-6=0

For the FOIL...

FIRST must be (-x)(x)=-x²

OUTER and INNER must add-up to +5x.

LAST must be (6)(1) or (1)(6) or (3)(2) or (2)(3) and one number must be negative to render the product of -6.

 

0=(-x+3)(x-2)

Let's FOIL...

FIRST...(-x)(x)=-x²

OUTER...(-x)(-2)=2x

INNER...(3)(x)=3x

LAST...(3)(-2)=-6

0=-x²+2x+3x-6

0=-x+5x-6

 

0=(-x+3)(x-2)

Either or both parenthetical equation(s) must equal zero...

0=-x+3............0=x-2

-3=-x...............2=x

3=x

 

x=3 and 2

Let's check our results with the original equation...

x^2+4x=2x^2-x+6.................x^2+4x=2x^2-x+6

3²+[(4)(3)]=[(2)(3²)]-3+6.......2²+[(4)(2)]=[(2)(2²)]-2+6

9+12=[(2)(9)]+3......................4+8=[(2)(4)]+4

21=18+3.................................12=8+4

21=21......................................12=12

 

 

Answer 2

So just use the answers to http://www.wyzant.com/resources/answers/29403/c_2_4x_2x_2_x_6.