I suspect that by the word "elimination," we mean to eliminate one of the variables from this system of equations. By doing so, we can then solve the remaining variable by the usual procedure & check our work by inserting our solutions into the original equations.
Substitution is a tactic we use to eliminate a variable. First manipulate the second equation & prepare it to substitute for x in the first equation:
x-y=-1
x=-1+y (adding y to both sides)
x=y-1 (commutative property)
Now, make the substitution:
2x-4y=-6
2(y-1)-4y=-6
By substituting the new version of the second equation, we have eliminated x from the equation.
Solve for y:
2(y-1)-4y=-6
2y-2-4y=-6 (distributive prop.)
-2y-2=-6 (combine like terms)
-2y=-4 (add 2 to both sides)
y=-4/-2 (divide both sides by -2)
y=2
Finally, find the value of x by substituting y in the equations:
x-y=-1
x-2=-1
x=1 (add 2 to both sides)
2x-4y=-6
2x-4(2)=-6
2x-8=-6
2x=-6+8 (add 8 to both sides)
2x=2
x=2/2 (divide both sides by 2)
x=1
I hope that helps!
Inactive Tutor
03/12/14