Jenny L. answered 03/11/14
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When the maximum number is N, the sum=(N+(N+1))/2
So 1+2+3+4+5+6+7+8+9+10= (10+11)/2
So the answer is C.
The more formal way is like this:
Consider 1+2+3
Assume S=1+2+3
S=1+2+3
S=3+2+1
Adding these 2 equations
2S= (1+3)+(2+2)+(3+1)
This equation has 3 pairs with each pairs equal to 4
2S= 4*3
S=4*3/2
In this equation, 4=1+max number (which is 3), 3 is the total number in S