Kenneth S. answered 03/12/17
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
As ALMOST ALWAYS IN GEOMETRY, you should make and label a diagram. In this case you can label the shorter sides as having length 2x EACH. Relying upon the 60o angle at the intersection of diagonals, and drawing a line segment from that intersection to the midpoint of one of the shorter sides, you will have formed a 30-60-90 triangle whose SHORTER SIDE measures x. Its hypotenuse will measure 2x due to the properties of 30-60-90 triangles. This means that each diagonal measures 4x.
Two diagonals measure 8x
Two shorter sides measure 4x
Total of the above is 12x = 36 in so x = 3 in. Therefore the diagonals measure 12 in.