5th grade word problem

Question

Nancy runs a dog obedience school. There are 58 dogs enrolled. There are 22 dogs in obedience class. There are 1/2 as many dogs in competition as there are in agility class. How many in each class?

Answer 1

Let x = Number of dogs in competition class 

     y = Number of dogs in agility class

and we know,

    22 =Number of dogs in obedience class

 

Assuming, each dog is enrolled in only one class,

Total dogs enrolled = x + y + 22

So, x + y + 22 = 58

      x + y = 58 - 22 = 36  .......................... (1)

We also know, there are 1/2 as many dogs in competition as there are in agility class.   

    x = y/2 .......................... (2)

 

Solving the two equations (1) and (2), we get  x= 12, y = 24 

 

So, the number of dogs in each class :  12 - competition, 22 - obedience, 24 - agility

 

 

Answer 2

a represents the number in agility

0.5a represents the number in competition

a + 0.5a + 22 = 58

Can you solve for a and answer?