Math Question Please Help

Question

a-3  - 2a-5= a+1-1

  4        2        3   6

 

Answer 1

(a - 3)/4 - (2a - 5)/2 = (a + 1)/3 - 1/6

3(a - 3) - 6(2a - 5) = 4(a + 1) - 2        multiply both sides by LCD, 12

3a - 9 - 12a - 30 = 4a + 4 - 2

 

Can you solve for a?

Answer 2

(a-3)/4 - (2a-5)/2 = (a+1)/3 - 1/6

 

Clear fractions by multiplying through by 12

 

12[(a-3)/4-(2a-5)/2] = 12[(a+1)/3 - 1/6]

3(a-3) - 6(2a-5) = 4(a+1) - 2

3a-9-12a+30 = 4a+4-2

-9a + 21 = 4a + 2

19 = 13a

19/13 = a

 

a= 19/13 = 1 6/13