
Parviz F. answered 03/06/14
Tutor
4.8
(4)
Mathematics professor at Community Colleges
P(X) = X ^6 -1
= (X^3 +1 ) ( X^3 - 1)
= ( X +1 ) ( X^2 - X +1) ( X -1 ) ( X^2 + X + 1)
X +1 = 0 X =-1 X -1 = 0 X =1
X^2 -X +1 = 0 X = 1/2 ± √[(1^2 - 4( 1, 1)] /2
X = 1/2 ± i √3
X ^2 + X + 1 = 0 X = -1/2 ±i√3/2