Brian P. answered 03/01/17
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It's pretty nice to use the equation D = rt to solve this problem. D means distance, r means rate or speed, and t means time. I'm going to make a rough sketch of what's going on here. The planes are traveling towards each other like this.
A-------------><--------B
"A" and "B" represent the airports. The left arrow will represent the faster plane, which is traveling 10 miles per hour faster. We don't know the exact speed, but we do know that it's 10 more than the slower one. Therefore, the speed for the fast plane will be "r + 10" and the slow plane's speed will be just "r."
Let's make an equation for the fast plane. I'll use subscripts of "f" to mean fast. Also, both planes are traveling for one and a half hours. In other words, their traveling for 1.5 hours, so assign t = 1.5 for both planes.
Df = rftf
Df = (r + 10)(1.5)
Now let's make the equation for the plane that's slow and takes its time.
Ds = (r)(1.5)
The weird part is to find the relationship between the two planes. Look at my lame sketch up above that represents the scenario. The two arrows represent the respective distances that both traveled. Because the two airports are 555 miles apart, the sum of their respective distances add up to 555.
Df + Ds = 555
Substitute the equations for Df and Ds into this.
Df + Ds = 555
(r + 10)(1.5) + (r)(1.5) = 555
1.5r + 15 + 1.5r = 555
3r + 15 = 555
3r = 540
r = 180
Now we know r = 180. We assigned the speed of the slow plane to be a plain old r, so 180 miles per hour is the speed of the slow plane. The fast plane has a speed that's 10 more, so the fast plane's speed is 190. I hope this helps, and good luck with your math class!
Al P.
I like the way you explained the answer. Good work. Just want to point out one minor calculation error. In solving for 'r' you had 3r=540 so r=180 MPH, and thus the faster plane traveled at 190 MPH.
Check: 180*1.5 + 190*1.5 = 270 + 285 = 555 mi
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03/01/17
Brian P.
Thank you for pointing that out. Apologies about it. I just fixed it!
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03/01/17
Nicole D.
03/01/17