Line in standard form

Question

write the equation of the line in standard form :

(-4, -6) ; m=2

Answer 1

Put m=2 and (-4,-6) into point-slope form of the equation of a line:

   y - y₁    = m(x - x₁)

   y - (-6) = 2(x-(-4))

   y + 6  =  2(x+4)

   y + 6 = 2x + 8

   2x - y = -2             [Standard Form looks like Ax+By=C]

 

Answer 2

Standard form:  Ax + By = C

 

To find the equation of the line, use the point-slope form:

 

y - y₁ = m(x - x₁)

y - (-6) = (-2)(x - (-4))

y + 6 = -2x - 8

 

y + 2x = -14    This is in Standard From

Answer 3

The equation in point-slope form is

 

y - y₁ = mx - mx₁

 

where:

m = slope

(x₁ , y₁) is any given point

 

 

Then the equation in standard form is

 

-mx + y = -mx₁ + y₁

 

 

All you have to do is plug in the given values.