the perimeter of the regulation singles court is 210 feet less that 3 times the width. what are the dimensions of the court?

Question

I need help to solve this problem. 

Answer 1

First, label the unknown quantities:

Let L be the Length of the rectangular court

Let W be the width of the court

Let P be the perimeter of the court

Next, write formulas involving those quantities:

(Perimeter: walk down one long side, and write down L feet,

then walk next to the short side, and write down W,

then walk back up the other long side, write down L,

finally, walk alongthe other short side, and write down W.

Total perimeter is L + W + L + W. once you gather similar terms, you get:)

P = 2L + 2W

and you have another formula involving P:

P = 3W - 210

since both formulas are equal to P, set them equal to each other:

2L + 2W = 3W - 310: Simplify this

2L = 1W - 310

while we don’t know enough to arrive at a number, we can see how they’re related:

2L = W - 310

L = W/2 - 310/2 = W/2 - 65

or

W = - 310 - 2L