
Arturo O. answered 02/18/17
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Jessica,
Are you familiar with the quadratic formula?
For
ax2 + bx + c = 0,
x = [-b ± √(b2 - 4ac)] / 2a
In this problem,
6x2 + 7x = 20
6x2 + 7x - 20 = 0
a = 6
b = 7
c = -20
Substitute these values into the quadratic formula to find two possible values for x.
Mayuran K.
02/18/17