algebra 1 help

Question

y²+6=6y The solution(s) is/are y=

 

Simplify your answer. Type an exact answer, using radicals as needed. Use integers or fractions for any numbers in the expression. Express complex numbers in terms of i. Type each solution only once. Use a comma to separate answers as needed.)

Answer 1

Hi Jessica, start by moving all terms to one side of the equal sign leaving 0 on the other side.

 

y² - 6y + 6 = 0

 

Use the quadratic equation to solve, where a = 1, b = -6, and c = 6:

 

y = (-(-6) ± √((-6)² - (4 * 1 * 6)))/(2 * 1)

 

y = 6 ± √(36 - 24))/2

 

y = 6 ± √(12)/2

 

y = 6 ± 2 *√(3)/2

 

y = 3 ± √(3)

 

Answers: y = 3 + √(3), y = 3 - √(3)

 

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