Andrew M. answered 02/12/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
n = #nickels
d = #dimes
there are 16 coins:
n + d = 16 ________ eqn 1
Total money is $1.20:
.05n + .1d = 1.20 __ eqn 2
from eqn 1 solve for n and substitute
into eqn 2
n = 16-d
.05(16-d) + .1d = 1.20
.8 - .05d + .1d = 1.20
.05d = .40
d = .40/.05
d = 8 dimes
n = 16-8 = 8 nickels
check: 8(.1) + 8(.05)
= .8 + .4
= $1.20