
Michael C. answered 01/28/17
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There are two motions when the marble exits the table
1. horizontal motion of 0.2m/s until the marble hits the floor and
2. vertical motion under gravity of 9.81 m/s^2
time taken to hit the floor under gravity, t = (2 * 0.8/9.81)^1/2 = 0.202 seconds (using h = 1/2*g*t^2)
displacement under constant velocity = velocity * time
horizontal displacement = horizontal velocity * time taken
horizontal distance = 0.2 m/s * 0.202 secs = 0.0404 m = 4cm