
Russ P. answered 09/30/14
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Fiona from the land of Microsoft,
Let x be the unknown speed of the current flowing down stream. Then,
(16 - x) is the average speed of the motorboat relative to the river bank heading upstream and fighting the current
(16 + x) is the average speed relative to the river bank coming back downstream when the current is helping
The distance, d(t) traveled in time t is measured on the river bank and is the same whether going there or coming back
The time of travel is however different because the current either slows down or speeds up the motor boat
Then d = st is the distance formula, but must use compatible units in all the variables
Hence d is in miles, s is in mph, and t is in hours, not minutes!
Going upstream: d = (16-x)(20/60) = (1/3)(16-x)
Coming downstream: d = (16+x)(15/60) = (1/4)(16+x)
The distances are equal since the starting and ending points are on the riverbank.
So (1/3)(16-x) = (1/4)(16+x) & multiplying left and right sides by 12 , we get rid of the fractions
So 4(16-x) = 3(16+x) and distributing/expanding: 64 - 4x = 48 + 3x
And 16 = 7x, so
x = 16/7 mph or 2.286 mph