-3<x−1≤2

-3 < x−1 ≤ 2

Add 1 to each of the 3 parts:

-2 < x ≤ 3

<----O========@----->

-2 3

This is a single variable graph on a single number line. There is a open dot at -2 and a closed dot at 3.

I'm not sure what all the other discussion is about.

Simple problem, as I see it.

## Comments

^{2}-2y+y^{2}-8y-2 i got 4y^{2}-10y-2^{2}-5y-1)^{2}^{2}-4x+6x-3^{2}+2x-3^{2 }and the same with 40b^{3}c^{6 }over -8b^{2}c^{2}=(-6a+b)(-6a+b)^{2}^{2}^{2}-6ab-6ab+b^{2}^{2}-12ab+b^{2}^{3}c^{6})/(-8b^{2}c)^{3}/b^{2}=b^{1}=b, because 3-2=1^{6}/c=c^{6}/c^{1}=c^{5}, because 6-1=5^{5}