Farrooh F. answered 01/15/17
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You have two equations:
2 + 3 y = 2 ---> I am guessing you had it like 2 x + 3 y = 2 instead.
x2 + y2 + 3 x y = -4
You can find the solution by using the substitution method. First, let us solve the first equation for x.
2 x + 3 y = 2
2x = 2 - 3y
x = 1 - (3/2) y
Now let us plug in this result into the second one:
x2 + y2 + 3 x y = -4
Notice that x2 + y2 +2 xy can be written as (x+y)2, therefore, we have:
(x+y)2 + xy = -4
[1 - (3/2) y + y]2 + (1 - (3/2) y) y = -4
[1 - (1/2) y]2 + y - (3/2) y2 = -4
1 - y + (1/4) y2 + y - (3/2) y2 = -4
-5/4 y2 + 1 = -4
-5/4 y2 = -5
y2 = 4
y = -2 or y = 2
Correspondingly
x = 4 or x = -2
Thus you would find:
(4, -2) and (-2, 2)
2 + 3 y = 2 ---> I am guessing you had it like 2 x + 3 y = 2 instead.
x2 + y2 + 3 x y = -4
You can find the solution by using the substitution method. First, let us solve the first equation for x.
2 x + 3 y = 2
2x = 2 - 3y
x = 1 - (3/2) y
Now let us plug in this result into the second one:
x2 + y2 + 3 x y = -4
Notice that x2 + y2 +2 xy can be written as (x+y)2, therefore, we have:
(x+y)2 + xy = -4
[1 - (3/2) y + y]2 + (1 - (3/2) y) y = -4
[1 - (1/2) y]2 + y - (3/2) y2 = -4
1 - y + (1/4) y2 + y - (3/2) y2 = -4
-5/4 y2 + 1 = -4
-5/4 y2 = -5
y2 = 4
y = -2 or y = 2
Correspondingly
x = 4 or x = -2
Thus you would find:
(4, -2) and (-2, 2)