Kenneth S. answered 12/14/16
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
Nevertheless, we can figure out how to solve this problem.
Outbound trip: D = (rate)(time) 12 = (x+7)(1-t)
Inbound trip: 12 = (x)(t)
Note that the rates differ by 7, with outbound being 7 mph faster, and total times = 1.
In the first equation, after distributing, you get 12 = x - tx + 7 - 7t
From the second equation we can take 12 = xt and substitute into the first, and then we have
12 = x - 12 + 7 - 7t
12 = x - 5 - 7t
0= x - 7t - 17; now we will substitute t = 12/x and we get
0 = x - 84/x - 17. We multiply all terms by x and finally we get this quadratic equation:
x2 - 17x - 84 = 0.
Solve this by factoring; the only valid answer is x=21 -- the rate in mph of the homebound part of the trip.
Check the answer on both trips!