Raymond B. answered 09/11/25
Math, microeconomics or criminal justice
high tide 58 feet deep, low tide 2 feet deep
high tide 6:30 am, low tide 6 hours and 12 minutes after high tide = 12:42 pm same day
trig function that fits, find water depth at noon. after 2pm, what time could a boat dock that needs 25 feet of water to come in
fit the data to f(x) = Asin(Bt+C) +D where A =Amplitude = (max-min)/2= (58-2)/2 = 56/2 = 28, B = pi/period, C = phase shift, D = midline = (max+min)/2 = average depth = (58+2)/2 = 60/2 = 30
y = f(x) = depth = 28sin(pit/6.7 +0) + 30
for t=0, depth = 28(0) + 30 = 58 for 6am. t=0 means 6 am
noon means t = 0+5.5 = 5.5
5.5 = 28sin(pit/6.7) + 30, solve for t than add 5 hours 30 minutes
25 = depth = 28sin(pit/6.7) +30
solve for t
-5/28 = sin(pit/6.7)
pit/6.7 = arcsin(-5/28)
t = (6.7/pi)arcsin(-5/28)
then add 5 hours and 30 minutes