Gregg K. answered 12/08/16
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How many at each price dd she purchase might be want you really want. If you want how many CDs were purchased that is in the problem, 9
Let's assume it's the first case
Let X = cheaper CD
Let Y = more expensive CD
X + Y = 9 (#1)
12X + 14Y = 114 (#2)
We can solve this system by using elimination
We will multiply equation #1 by 12
12X + 12Y = 108 (#3)
12X + 14Y = 114 (#2)
Now subtract #3 from #2
2Y = 6
Now divide by 2
Y = 3
Sabrina bought 3 of the more expensice CDs and thus bought 9 - 3 or 6 of the cheaper CDS