Zachariah C.

asked • 12/03/16

Simple Trig, got lost and need help.

Solve the given equation over the interval [0,2): 2sinx+ (sqrt 3) sin^2x=-(sqrt 3) cos^2x
A. x=0, and x=(pi/2), and x=(3 pi/2), and x=2(pi)x=(3 pi/2), and x=(7 pi/2)
b. x=(4 pi/3) and x=(5 pi/3)
c. x=(7 pi/6) and x=(11 pi/6)
d. x=(pi/6) and x=(5 pi/6)

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