what is the slope for( 5/6 and -4) and -1/3 -1/3

Question

i need help i am very good at math and bad at reading

Answer 1

Slope = (y2 - y1)/x2-x1) = (-1/3 -(-4))/(-1/3 - 5/6) = (11/3)/(-7/6) = 11/3 x (-6/7) = -22/7

:)

Answer 2

Hi Malachi;

I believe these are coordinates...

(5/6,-4) and (-1/3,-1/3)

Slope is change-of-y divided by change-of-x.

m=(y-y₁)/(x-x₁)

m=[(-4)-(-1/3)/[(5/6)-(-1/3)]

Subtracting a negative number is the same as adding a positive number...

m=[(-4)+(1/3)]/(5/6)+(1/3)]

-4+1/3=-3 2/3=-11/3

(5/6)+(1/3)=(5/6)+(2/6)=7/6

m=(-11/3)/(7/6)

Let's flip 7/6 in the denominator so it becomes 6/7 in the numerator.

m=(-11/3)(6/7)

(-11)(6)=-66

(3)(7)=21

m=-66/21

Both numbers are divisible by 3...

m=-22/7, -3 1/7