Gene G. answered 11/25/16
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Retired Electrical Engineer Helping People Understand Algebra
Let M be Maggie's age and B her brother's age.
Twice Maggie's age is 2M.
13 years younger than that is 2M-13.
B = 2M-13
The sum of their ages is
M + B = 29
B = 2M-13
M + B =29
We have two equation and two unknowns. Since one of them is B in terms of M, substitution is easy.
Substitute (2M-13) for B in the second equation and solve for M.
M + (2M-13) = 29
3M - 13 = 29
3M = 42
M =14 Answer
You could also solve for B.
14 + B = 29
B = 15