^{2 }+ 15x -9

^{2}+ 15x -9

^{2}+5x-3)

^{2}+5x-3)=0

^{2}+5x-3=0

^{2}

^{2}

^{2}+6x-x-3

^{2}+5x-3

6x^{2 }+ 15x -9

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Hi Susan;

6x^{2} + 15x -9

3(2x^{2}+5x-3)

We can set this equal to zero...

3(2x^{2}+5x-3)=0

The parenthetical equation must equal zero. Therefore, we can eliminate the 3...

2x^{2}+5x-3=0

For the FOIL...

FIRST must be (2x)(x)=2x^{2}

OUTER and INNER must add-up to 5x.

LAST must be (3)(1) or (1)(3) and either number must be negative to produce -3.

(2x-1)(x+3)

Let's FOIL...

FIRST...(2x)(x)=2x^{2}

OUTER...(2x)(3)=6x

INNER...(-1)(x)=-1x=-x

LAST...(-1)(3)=-3

2x^{2}+6x-x-3

2x^{2}+5x-3

(2x-1)(x+3)=0

Either or both parenthetical equations must equal zero...

2x-1=0

2x=1

x=1/2

x+3=0

x=-3

Parviz F. | Mathematics professor at Community CollegesMathematics professor at Community Colle...

You want to solve:

6X^2 + 15X - 9 =0

3 ( 2X^2 + 5X - 3 )

3 ( 2X^2 + 6X - X -3 ) =0

3 [ 2X( X +3 ) - ( X +3 ) ] =0

3 [ ( X +3 ) ( 2X -1) ] =0

X +3 = 0 X = -3 , 2X -1 = 0 X = 1/2

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