Olivia B.
asked 11/15/16Finding the values for Integral Notation.
The question says: Express the area of the region under the curve
y = 6x^3 + 5x^2
and above the x-axis as a definite integral.
y = 6x^3 + 5x^2
and above the x-axis as a definite integral.
It gives the long s with blanks to the right at the bottom and top- I think this is the A and B value, and a blank to the right of those which is have no idea what that is. I don't understand what it is asking or what to do. Please help me?
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1 Expert Answer
Michael J. answered 11/15/16
Tutor
5
(5)
Applying SImple Math to Everyday Life Activities
You need to first find the lower and upper bounds. To this this, find the intersection between the function and x-axis.
Set the function equal to zero.
6x3 + 5x2 = 0
x2(6x + 5) = 0
x = 0 and x = -5/6
Your lower bound is x=-5/6.
Your upper bound is x=0.
So you have
0-5/6 ∫(6x3 + 5x2)dx
Now you can integrate.
Olivia B.
Okay so I followed getting the A and B values. However, when I go to integrate, I keep getting zero using this notation. Am I doing something wrong?
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11/15/16
Olivia B.
Oh wait, I think I see where I messed up. Thank you!
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11/15/16
Michael J.
You have first find the indefinite integral. Then evaluate that integral by plugging in the bounds. The integral using the upper bound minus the integral using the lower bound.
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11/15/16
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Mark M.
11/16/16