Vivian L. answered • 02/04/14

Tutor

3
(1)
Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACH

Hi Dalia;

(x-5/x

^{2}-25) - (3/x+5)= A/BI think this is...

[(x-5)/(x

^{2}-25)]-[3/(x+5)]=A/B(x

^{2}-25)=(x+5)(x-5){(x-5)/[(x+5)(x-5)]}-[3/(x+5)]=A/B

In the first bracketed equation, the (x-5) in the numerator and denominator cancel...

{(x-5)/[(x+5)(x-5)]}-[3/(x+5)]=A/B

[1/(x+5)]-[3/(x+5)]=A/B

Let's combine numerators...

(1-3)/(x+5)=A/B

-2/(x+5)=A/B

For B to be a polynomial with a leading coefficient of 1, then in such equation, the vertex is...

-b/2a=1

The easiest resolution for this is...

-b=4, b=-4

2a=4, a=2

2x

^{2}-4x+?(2x-14)(x+5)

**2x**

^{2}-10x-70.......This is the B equation.-2/(x+5)=A/B

Let's multiply the top and bottom of the left side by (2x-14)

[-2(2x-14)]/[(x+5)(2x-14)]=A/B

-2(2x-14)

**-4x+28.........This is the A equation.**