-3[(4-3)^2+6]^2

Question

I need help with this

Answer 1

The order of arithmetic operations is given by the acronym PERAMDAS:

    1. <P>arentheses

    2.  <E>xponents

    3.  <R>adicals

    4.  <A>bsolute value

    5.  <M>ultiplication

    6.  <D>ivision

    7.  <A>ddition

    8.  <S>ubtraction

Let's apply PERAMDAS to our problem:

     1.  Expression to evaluate:  -3[(4-3)^2+6]^2

     2.  First, do subtraction operation to eliminate inner parenthesis:  -3(1^2+6)^2

     3.  Next, do exponent operation in parenthesis: -3(1+6)^2

     4.  Next, do addition operation in parenthesis:  -3(7)^2

     5.  Next, do exponent operation on number in parenthesis:  -3(49)

     6.  Last. do multiplication operation with with number in parenthesis to obtain answer of -147 

Answer 2

Hello,

Use order of operations (PEMDAS). Solve the inner bracets first.

Expression will become

         -3[(1)^2+6]^2

Next, solve the inner exponent

          -3[1+6]^2

Add the integers inside the parenthesis

           -3[7]^2

Solve the exponent part next

            -3 * 49

Multiply them 

             -147 (answer)

I hope this helps you.