Victoria M.

asked • 11/04/16

The following polynomial is not factored completely. Original Polynomial: 6a^3b+36a^2b+48a^4b Factored Polynomial: 3ab(2a^2+12a+16a^3)

Part A: Explain why the factored polynomial above is not factored completely.
 


Part B: Factor the original polynomial completely.
 

1 Expert Answer

By:

Mark M. answered • 11/04/16

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2, 12, and 16 have a common factor.
What is it?
Can you now factor completely?
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Elizabeth H.

You can also pull out an a.
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11/04/16

Mark M.

So true! An "a" can be factored out (they don't like to be pulled).
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11/04/16

Victoria M.

For B would the answer be 6a^2(8a^2+a+6)b    Can you please help me with A and Explain why the factored polynomial above is not factored completely. can you tell me if my answer for B is correct or incorrect.
 
Thank you 
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11/06/16

Mark M.

B.
6a2b(a + 6 + 8a2)
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11/06/16

Victoria M.

Thank for helping me with part B but can you also help me with part A please
 
 
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11/07/16

Mark M.

"Factored completely" means that ALL common factors are factored out. In A) the commons factors 2 and a remained in the parenthesis.
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11/07/16

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