Peter G. answered 10/13/16
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A function is invertible if it is one-to-one. A strictly increasing function, or a strictly decreasing function, is one-to-one.
If you can demonstrate that the derivative is always positive, or always negative, as it is in your problem, then you've shown that the function is one-to-one, hence invertible. Technically, the derivative can also be zero at isolated points, just not zero on an interval.
For your case, note that the derivative is a sum of squares and a positive constant, hence is, always positive.