Kenneth S. answered • 10/11/16

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Question is equivalent to P(4 or 5 reds, drawing 5 cards), which will be the sum of the following two possibilities.

P(all red) =

_{26}C_{5}/_{52}C_{5}P(4 red, 1 black) =

_{26}C_{4}•_{26}C_{1}/_{52}C_{5}