Find the ratio of the area of triangle XBY to the area of triangle ABC for the given measurements, if

XY = 2, AC = 3

A. 1/3

B. 2/3

C. 4/9

Image: https://media.glynlyon.com/g_geo_2013/8/23183_5.gif

Find the ratio of the area of triangle XBY to the area of triangle ABC for the given measurements, if

XY = 2, AC = 3

A. 1/3

B. 2/3

C. 4/9

Find the ratio of the area of triangle XBY to the area of triangle ABC for the given measurements, if

XY = 2, AC = 3

A. 1/3

B. 2/3

C. 4/9

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Since triangle ABC and triangle XBY are similar

XY/AC = YB/CB = XB/AB = 2/3

Therefore sides of triangle XBY will be 2/3a, 2/3b, 2/3c

Use Heron's formula to find area of a triangle

Area of triangle ABC = sqrt ( s(s-a)(s-b)(s-c)) where s = 1/2(a+b+c)

Area of triangle XBY = sqrt( s'(s'-a')(s'-b')(s'-c') where s' = 1/2(2/3a + 2/3b + 2/3c) = 2/3s, a'=2/3a, b'=2/3b, c'=2/3c

Therefore area of traingle XBY = sqrt ( 2/3s(2/3s - 2/3a)(2/3s - 2/3b)(2/3s - 2/3c)

= sqrt(2/3 x 2/3 x 2/3x 2/3 (s(s-a)(s-b)(s-c)))

= 4/9 sqrt(s(s-a)s-b)(s-c)) = 4/9 Area of triangle ABC

Therefore ratio of the area of triangle XBY to the area of triangle ABC = 4/9

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